BKT - Q7

What should the formula be for P(Ln-1|Result)?
A. df3.loc[df3["right"] == 1, "P(Ln-1|Result)"] = df3.loc[:, "P(Ln-1)"]*(1-t)/((df3.loc[:, "P(Ln-1)"]*(1-t)) + (1-df3.loc[:, "P(Ln-1)"])*t)
B. df3.loc[df3["right"] =! 1, "P(Ln-1|Result)"] = df3.loc[:, "P(Ln-1)"]*t/((df3.loc[:, "P(Ln-1)"]*t) + (1-df3.loc[:, "P(Ln-1)"])*(1-t)
C. df3.loc[df3["right"] == 1, "P(Ln-1|Result)"] = df3.loc[:, "P(Ln-1)"]*s/((df3.loc[:, "P(Ln-1)"]*s) + (1-df3.loc[:, "P(Ln-1)"])*g)
D. df3.loc[df3["right"] != 1, "P(Ln-1|Result)"] = df3.loc[:, "P(Ln-1)"]*s/((df3.loc[:, "P(Ln-1)"]*s) + (1-df3.loc[:, "P(Ln-1)"])*(1-g))
E. df3.loc[df3["right"] == 1, "P(Ln-1|Result)"] = df3.loc[:, "P(Ln-1)"]*(1-g)/((df3.loc[:, "P(Ln-1)"]*(1-g)) + (1-df3.loc[:, "P(Ln-1)"])*s)
F. df3.loc[df3["right"] != 1, "P(Ln-1|Result)"] = df3.loc[:, "P(Ln-1)"]*g/((df3.loc[:, "P(Ln-1)"]*g) + (1-df3.loc[:, "P(Ln-1)"])*(1-s))
G. df3.loc[df3["right"] == 1, "P(Ln-1|Result)"] = df3.loc[:, "P(Ln-1)"]*(1-s)/((df3.loc[:, "P(Ln-1)"]*(1-s)) + (1-df3.loc[:, "P(Ln-1)"])*g)
H. df3.loc[df3["right"] != 1, "P(Ln-1|Result)"] = df3.loc[:, "P(Ln-1)"]*(1-s)/((df3.loc[:, "P(Ln-1)"]*(1-s)) + (1-df3.loc[:, "P(Ln-1)"])*g)
Use Comma to seperate multiple options, such as A,B


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